At last!!!Actually ... it is his son ... the solpadine worked !!
The pictured guy has a father who is the son of my father 'me'. So it must be son of 'me'.
Unless it's somewhere in the deep south, in which case it's anyone's guess, up to and including the dog.Actually ... it is his son ... the solpadine worked !!
The pictured guy has a father who is the son of my father 'me'. So it must be son of 'me'.
Can we go onto now Bunny?
You hum it - Norman will play something else altogether!Might I suggest that you have too much time on your hands?
eh - no - he is looking at a photo of himself
another way.......
Pat is looking at a picture of Pat
My father is Tony
See this man in the photo Pat - his father is Tony
I am my fathers son - the man in the photo is my fathers son -so man in photo is Pat (himself)
This man's father = My father's son
My father's son = me.
==> This man's father = me
==> This man = my son
Fine - except that has nothing to do with the original riddle:eh - no - he is looking at a photo of himself
another way.......
Pat is looking at a picture of Pat
My father is Tony
See this man in the photo Pat - his father is Tony
I am my fathers son - the man in the photo is my fathers son -so man in photo is Pat (himself)
This is as good as it was in the pub except quieter
Ok Ok Ok - enough of the hard stuff, I want to chill out and relax a bit. Am just about to get stuck into a bit of quantum physics there (jeez I really look forward to Thursday nights!).... I've a little teaser there for ya though if you have 2-3 minutes to spare - before yez all go out and get wasted..... have fun...
Planets move in ellipses with the Sun at one focus. Ellipses can be described in terms of their semi-major axis, a, (basically the longest radius) and their eccentricity (basically how squashed the ellipse is: e=0 is a circle, a fully squashed ellipse looks like a line and has e=1).
r=a(1-e2)/(1+e cos()); rmin= a(1-e); rmax=a(1+e)
, the polar angle from closest approach is given the odd name: true anomaly. The timing of the motion (i.e., when the planet or electron has a particular ) is a bit complex. The game is to express the true anomaly () in terms of the eccentric anomaly (u) and then find an expression relating time and the eccentric anomaly.
Time starts now, you have 3 minutes.
This is the tenpenny question and Norman is in the background playing Also sprach Zarathustra by Richard Strauss in a bossa nova tempo. Stop the lights!Ok Ok Ok - enough of the hard stuff, I want to chill out and relax a bit. Am just about to get stuck into a bit of quantum physics there (jeez I really look forward to Thursday nights!).... I've a little teaser there for ya though if you have 2-3 minutes to spare - before yez all go out and get wasted..... have fun...
Planets move in ellipses with the Sun at one focus. Ellipses can be described in terms of their semi-major axis, a, (basically the longest radius) and their eccentricity (basically how squashed the ellipse is: e=0 is a circle, a fully squashed ellipse looks like a line and has e=1).
r=a(1-e2)/(1+e cos()); rmin= a(1-e); rmax=a(1+e)
, the polar angle from closest approach is given the odd name: true anomaly. The timing of the motion (i.e., when the planet or electron has a particular ) is a bit complex. The game is to express the true anomaly () in terms of the eccentric anomaly (u) and then find an expression relating time and the eccentric anomaly.
Time starts now, you have 3 minutes.
I'll second that after reading the responsesI propose that nutty nut is banned from this forum for giving me a headache today.
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