LDFerguson
Registered User
- Messages
- 4,717
Can anyone tell me why this equation is unusual? (This is not a trick question or a joke by the way.)
(a+b)^2 = a^2 + 2ab + b^2
(a+b)^2 = a^2 + 2ab + b^2
It works for any values of a and b?
That's the answer?Yup - I only read about this recently (in a thriller novel, oddly enough) - I believe such equations are known as identities, where you can insert any value for a or b (or other variable) and the equation will still work.
That's the answer?
I thought the whole idea of algebra was that you could insert any value for the variables. How does this make the equation any different to any other equation?
how is it different to:
(a)(a) = a^2 ?
Because it can be used to prove Pythagoras' Theorem?
Homer
Blazes. When I read this, I thought it was unusual for an equation with two variables to have freedom for either one to have any value. Darn you Stieg Larsson!
For example, 2(a) + (b) = 6(a) only works where (b) = 4(a)
But I think I'm actually just showing up the fact that the last time I studied algebra (badly) was approaching 25 years ago.
I think I'll stop digging.
For example, 2(a) + (b) = 6(a) only works where (b) = 4(a), so you cannot use any numbers you like for (a) and (b).
That's the answer?
I thought the whole idea of algebra was that you could insert any value for the variables. How does this make the equation any different to any other equation?
how is it different to:
(a)(a) = a^2 ?
In the OP's example, it's the same equation at both sides of the equal sign. It's like saying:Not all equations mean that the two expressions are equal for whatever value we give the variables involved. When it is, it is known as an identity. Otherwise it is just known as an equation.
In the OP's example, it's the same equation at both sides of the equal sign. It's like saying:
2y = 2y
or
(x^2)w+7/t = (x^2)w+7/t
etc...
Of course the expression will be equal for whatever values are given.
I'm a bit disappointed with this to be honest.